[课堂练习]
2
现有公式(x)(y)(z)[(A∨B)∧C],在经过减少否定符号的域后得到公式为:  
 
A (x)(y)(z)[(AB)∨C]
B (x)(y)(z)[(A∨B)C]
C (x)(y)(z)[(A∨B)C]
D (x)(y)(z)[(A∨B)C]
E (x)(y)(z)[(A∨B)C]
  F (x)(y)(z)[(A∨B)C]  

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